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Databases Reporting with SQL Date and Time Functions Practice Session

Posted by tonypitkin2
tonypitkin2
Courses Plus Student 1,950 Points

Formatting Dates in a simple way?

From the practice session:

Format dates in all the loans table in the UK format without the year. For example, April 1st is 01/04.

I came up with the following:

SELECT id, book_id, patron_id, STRFTIME("%m/%d", loaned_on) AS "loaned_on", STRFTIME("%m/%d", return_by) AS "return_by", STRFTIME("%m/%d", returned_on) AS "returned_by" FROM loans

My question: Is there a way to make the above more efficient?

3 Answers

Steven Parker
Steven Parker
231,272 Points
Steven Parker
Steven Parker
231,272 Points

That's pretty close, unless you interpret the instructions to imply "return only the dates...", or to modify the dates in the table instead of just showing them.

Otherwise, the only issue is that they asked for the "UK format" which puts the day before the month.

tonypitkin2
tonypitkin2
Courses Plus Student 1,950 Points

Thanks Steven!

rudyolsson
seal-mask
.a{fill-rule:evenodd;}techdegree
rudyolsson
Full Stack JavaScript Techdegree Student 18,111 Points
rudyolsson
.a{fill-rule:evenodd;}techdegree
rudyolsson
Full Stack JavaScript Techdegree Student 18,111 Points

Your format is a little off, it should be dd/mm. For a simpler interpretation of what they were asking here are only the dates without aliases. 

SELECT STRFTIME("%d/%m", loaned_on), STRFTIME("%d/%m", return_by), STRFTIME("%d/%m", returned_on) FROM loans;
Anshul Laikar
Anshul Laikar
4,428 Points
Anshul Laikar
Anshul Laikar
4,428 Points

This is what I came up with, in case they wanted us to actually replace the values given to us:

UPDATE loans 
SET loaned_on = STRFTIME("%d/%m", loaned_on), return_by = STRFTIME("%d/%m", return_by), returned_on = STRFTIME("%d/%m", returned_on);