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3,400 Points(Python3.6) ShoppingList program gets 'break' error
I got the program to run using a while loop but I am having a problem getting it to run using a function. I have gone through it a couple times and think it looks ok, but I keep getting a " syntaxError: break outside loop" , this is what I have:
print("Let's make a shopping list, breh!")
print("Add new items one at a time, type, 'DONE' to finish")
shopping_list = []
def shopping():
new_item = input("> ")
if new_item.upper() == 'DONE':
break
shopping_list.append(new_item)
return shopping_list
print("Here's your shoping list, breh!")
print(shopping_list)
any ideas?
1 Answer
akhter ali
15,778 Pointsbreak
is not meant for if/else condition, break is meant to break out of for/while
loops. Your break statement is invalid.
Take the example from the link below, break is breaking out of the inner for
loop and only runs if
the condition is True/False