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JavaScript JavaScript and the DOM Making Changes to the DOM Modifying Elements

Challenge Task 2 of 2 Q: Next, set the text content of the <p> element with the class info to

Challenge Task 2 of 2 Q: Next, set the text content of the <p> element with the class info to the value stored in inputValue.

A:...?

Challenge Task 1 of 2 Q: Select the <input> element and assign its value to the variable inputValue.

A: var inputValue = document.querySelector('input').value;

<!DOCTYPE html> <html> <head> <title>DOM Manipulation</title> </head> <link rel="stylesheet" href="style.css" /> <body> <div id="content"> <label for="linkText">Link Text:</label> <input type="text" id="linkText" value="sample text"> <p class="info"></p> </div> <script src="app.js"></script> </body> </html>

i tried to answer Challange 2.2 , but couldn't find the answer?

could some on help me out?

love to hear from you.

app.js
var inputValue = document.querySelector('input').value;
index.html
<!DOCTYPE html>
<html>
    <head>
      <title>DOM Manipulation</title>
    </head>
    <link rel="stylesheet" href="style.css" />
    <body>
      <div id="content">
        <label for="linkText">Link Text:</label>
        <input type="text" id="linkText" value="sample text">
        <p class="info"></p>
      </div>
    <script src="app.js"></script>
  </body>
</html>

5 Answers

let inputValue = document.querySelector('input').value;

let p = document.querySelector('p').textContent = inputValue;

thank you so much!!!

Any time. Keep coding :)

const inputValue = document.getElementById('linkText').value;

const pSelect = document.getElementsByClassName('info')[0].textContent = inputValue;

It is because getElementsbyClassName returns an array like value a collection :D.

why wouldnt this work:

const inputValue = document.getElementById('linkText').value;

const pSelect = document.getElementsByClassName('info').textContent = inputValue;

Thxs for the reply… makes sense! Wonder if the inputValue will be formatted into an array within the β€˜p’ tags

Thanks again for the quick response :)

no problem