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JavaScript AJAX Basics Programming AJAX Check for the correct ready state

Posted by Fabiola Barrientos
Fabiola Barrientos
9,467 Points

I dont know what to do

Im stuck!!!!

app.js 
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if(xhr.readyState === 4) {
    if(xhr.status === 200) {
      document.getElementById("sidebar");
    }
  }
};
document.xhr("sidebar")
xhr.open('GET', 'sidebar.html');
xhr.send();
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>

2 Answers

David Vaughn
David Vaughn
2,582 Points
David Vaughn
David Vaughn
2,582 Points

document.getElementById('sidebar').innerHTML = xhr.responseText;

I'll save someone the headache.. I feel like this is something I wasn't shown which is way too typical of coding courses. Plus the presentation for me in this has been almost completely unretainable and I've had to re-watch most of these videos three times. I hear the words, and deathly try to zoom in on his workspace, but I forget it as soon as it's delivered. Thank microsoft for notepad. practice required guys, not just a quick video.

Steven Parker
Steven Parker
231,268 Points
Steven Parker
Steven Parker
231,268 Points

First, remove what's currently on line 9, it's not valid.

Then, step 4 says, "Now use a DOM element's innerHTML property to set the HTML inside the sidebar div to the server's response.". You already coded the part that selects the element in task 3, so now (on the same line) you need to access the innerHTML property of it. This will be the target of an assignment.

Then access the server's response (hint: it's a property of xhr) as the source of the assignment.