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Python Introducing Lists Using Lists Review Split and Join

Mikael D.D
PLUS
Mikael D.D
Courses Plus Student 2,080 Points

Quiz question 2 on review split and join

Review Split and Join Quiz

Question 1 of 2

If I had a list and I wanted to turn it into a string by combining each value together with a specified separator.

What method would I use?

A split. It's on lists.
B join. It's on lists.
C split. It's on strings.
D join. It's on strings.

What do we mean by: "I'ts on lists", "its on strings"

My brain is having a hard time parsing this question. Can someone please explain to me the "Its on" part...not sure i get it

So far, my understanding is that the Join method will output each element of a list as a clean compact string that we can display to a user. On the other hand, the split method does the opposite it turns a string into a list that we can play with.

2 Answers

Steven Parker
Steven Parker
231,268 Points

Methods are associated with different kinds of things. The phrase "it's on" is being used here to refer to the thing the method is associated with. This would also be the thing you would connect the method to using the membership operator (a dot: "."). So for generic examples:

"a string".method(["a", "list"])  # this method is "on" strings, and takes a list argument
["a", "list"].method("a string")  # this method is "on" lists, and takes a string argument

Since you know the name of the method, that puts you halfway there. Now if you identify the syntax you can pick the correct answer.

Mikael D.D
Mikael D.D
Courses Plus Student 2,080 Points

Crystal clear explanation as usual...Thank you Steven

In the Python docs join() is listed as a string method. It's kind of a trick question because you'd expect it to be a list method for what you stated above. "It's on" is another way of saying is a string/list method.

Mikael D.D
Mikael D.D
Courses Plus Student 2,080 Points

I need to cultivate the lifetime habit of reading the Python Doc related to each lesson.

Thank you Kris, for both the link and the hint ;)