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Start your free trialRobert Femi
689 PointsThis one should be short and sweet. Challenge Task 1 of 1
Why isn't the code accepted if I put ("True") and ("False") but it's accepted if remove brackets and quotation marks? Spent a LONG time figuring that out and would like to learn why so at least it won't be a complete waste of time. Would appreciate if someone can explain that to me. Many thanks.
def even_odd(number):
if number % 2 == 0:
return ("True")
else:
return ("False")
1 Answer
Alex Koumparos
Python Development Techdegree Student 36,887 PointsHi Robert,
Strictly, the problem is just with the quotation marks, not with the parens.
return (True)
will pass but
return ("True")
will not.
This is because True
and "True"
are completely different data types. True
is a boolean (a data type that can only ever be True
or False
, and Python can understand semantically what true and false mean) and "True"
is a string (and Python doesn't generally have any way to understand what is semantically in a string, just that it is a sequence of characters).
As for the parentheses, they are completely redundant and should be removed.
Cheers
Alex
Robert Femi
689 PointsRobert Femi
689 PointsThanks Alex.