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JavaScript AJAX Basics AJAX Concepts Finish the AJAX Request

Posted by Carolina Madella
Carolina Madella
978 Points

what's wrong with request.open('GET', 'sidebar.html');

the variable is called request and I need to open a AJAX request. It says that I need to specify the method which is 'get'

app.js 
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
  request.open('GET', 'footer.html');
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Your code line is fine, but it needs to be located after the function definition instead of inside it.