Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
taliarosen
2,492 Pointswhy is my variable not being a variable
the variable "count" is not being recognized as a variable and so I'm not getting the right output
import re
# EXAMPLE:
# >>> find_words(4, "dog, cat, baby, balloon, me")
# ['baby', 'balloon']
def find_words(count, string):
return re.findall('\w{count,}', string)
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsHey taliarosen, you are on the right path.
As written the letters “count” are going to be seen as a string. The variable needs to be evaluated as an integer before incorporating it into the string.
The hard part is that most formatting syntaxes use the curly brackets as field identifiers and may be confused by the regex count specifier.
To signify to keep (or escape) a literal curly bracket, instead of using it as a field identifier, use a doubled curly brace. This means you might see three in a row: two for the literal curly brace and on for the field marker.
So if you convert your regex into an f-string it would look like:
f'\w{{{count},}}'
# LLF F LL
# L marks Literal curly bracket
# F marks field curly bracket
Post back if you need more help. Good luck!!!